3y^2+18y=-105

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Solution for 3y^2+18y=-105 equation: 



3y^2+18y=-105

We move all terms to the left:

3y^2+18y-(-105)=0

We add all the numbers together, and all the variables

3y^2+18y+105=0

a = 3; b = 18; c = +105;
Δ = b2-4ac
Δ = 182-4·3·105
Δ = -936
Delta is less than zero, so there is no solution for the equation

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